This is a video on ANOVA The question states: A study was done to determine if the average amount spent on

textbooks per student is the same for LTCC, SAC City College, Solano College and De Anza College. What can be concluded at the 0.05 level of significance. So here’s the data and notice that there were four

students each for L TCC, Sac City, Salano, and De Anza, and we have the amount they spent on books. I want to perform an ANOVA test, so for the null

hypothesis on ANOVA, that means all the means

are the same. In particular H0 is that mu1 equals mu2 equals mu3 equals mu4. The alternative hypothesis is the opposite which means at least two of the

means are different from each other. so in order to perform an ANOVA test I will use a

calculator. So here’s a calculator. For ANOVA, I needed to first put in my data so I

go to STAT and then EDIT. I need a clear out the four lists: L1, L2, L3, L4

because I have four different colleges with data. So, let’s clear them out. OK, I’ve cleared my data. Now I enter my data.

For L1 I’ll put the LTCC Data for money spent on

books which is 248, ENTER, and then I put in the rest. and for L2 that’s the Sac City data. That’s 292, ENTER and I put in the rest for SAC City. for L3 I put in the Salano data. That’s 164. ENTER, and then I put in the rest. and then finally, let’s put in the De Anza data. That’s 106 ENTER and the rest. And finally 162. OK, now they have all my data entered let’s go to

the ANOVA test. I use STAT and then TESTS. I go to the UP arrow and the very last item is

ANOVA so I hit enter on ANOVA. and then I need a tell it that I’m looking at L1, L2,

L3, and L4 for my four lists. So 2nd L1 , 2nd L2, 2nd L3, 2nd L4 I end the parentheses and hit ENTER. OK, here is my the F statistic which is 1.65 about and the P-value which is about 0.229698

etcetera. and that’s important thing is the P-value. so let’s go back to the PowerPoint So here’s the PowerPoint. Our P-value was about 0.2297 and that’s greater than the level of significance

0.05 which is Alpha. When the P-value is greater than

the level of significance. That means we fail to reject the null hypothesis. The statement is that there is insufficient evidence to conclude that there is a difference between the mean book

expenditures at the four community colleges. so I’m done concluding. Let’s look at the requirements that we need in

order to perform an ANOVA test. The first one is that the distribution at each college must be normal. The second is that the standard deviations are

the same at all four colleges and the third is that the samples are randomly

taken and independent from each other. OK, these assumptions may or may not be true, but if they’re true then we can go ahead and

perform an ANOVA test. And I’m done with the problem.

Great video, thanks a bunch!

thanks đź™‚ but i wonder why my professor teaches a different assumption, that the smallest Std. Dev. times 2 is greater than the largest standard deviation? I dont even know how to find that on my ti-84.. :/

My college just taught us to use the F-ratio and C.V . Excuse me, what is the P value stands for ?

Oh my gosh. I was absent during this lesson and I couldn't figure out the calculator commands! Thank you so much!

Awesom video. You are the best! thanks.

haha I forgot how to use anova and I needed for my final for stats! well you deserve that like!

This should be renamed to say "One-Way ANOVA" not simply ANOVA

thank god I thought I had to do this all by hand ;_;